pn=1+∑i=12n⌊(n∑ij=1⌊(cosπ(j−1)!+1j)2⌋)1n⌋p_{n}=\displaystyle 1+\sum_{i=1}^{2^{n}}\left \lfloor(\frac{n}{\sum_{i}^{j=1}\left \lfloor(\cos\pi\frac{(j-1)!+1}{j})^{2}\right \rfloor})^{\frac{1}{n}}\right \rfloorpn=1+i=1∑2n(∑ij=1⌊(cosπj(j−1)!+1)2⌋n)n1